[Aztlan] Mesoamerican Calendar

[Rene Hauron]

 Dear listeros
I have some questions I would like to find answers.
First, the reason for setting the Mesoamerican calendar as having three sets
of accounts. A 365-day calendar, a calendar of 260 days and the third 18,980
days.
Apparently they are silly questions, but as tracks that exist in the pyramid
which withdrew those settings are not exactly those that could be the
logical call.
The 365-day calendar results from the multiplication of the three steps of
ninety-one steps over the sum of over one step of the upper platform for a
total of 365 steps (days).
To achieve the third system of accounts 365 days multiplied by 52,
corresponding to 52 tablets of only one of the four faces of the pyramid.
The pyramid has four sides with 91 steps.
The pyramid also has four sides 52 tablets each.
Because for 365 days were used to obtain the four faces of 91 steps and get
the other system, 18,980 days were spent only one side? 365x52 = 18,980
The most logical thing would also divide the four sides of 52 Lapides each
and totaling 208 gravestones. 52x4 = 208
I understand that in this way, the calendar as we know it would not be
correct.
Can someone please explain these differences?



-- 
René Haurón (Edgardo S Dal Molin)

renehauron at gmail.com

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